Question

A vertical tower PQ subtends the same angle of 30 degree at each of the two places A and B, 60 m apart on the ground. If AB subtends an angle of 60 degree at P, the foot of the tower, find the height of the tower

Answer given = 20√3 m
Show step wise

Answer 1

Answer:

Step-by-step explanation:

the triangle ABP s isosceles wid centrl angle=120...AB=60..AP=BP=60/rt 3=20 rt 3...

height f tower=20 rt3/rt 3=20..!!!

Answer 2

step by step explanation:

1. Answer :

20 root 3 m