A vertical tower stands on a horizontal and is surmounted by a flagstaff of height 7m. from a point on the plane,the angle of elevation of the bottom of the flagstaff is 30° and that of the top of flagstaff is 45°.Find the height of the tower. Tell Fast
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Answered by
5
Answer:
⇒ In △CBD,tan30
o
=
BC
BD
⇒
3
1
=
x
h
⇒ x=
3
h ----- ( 1 )
⇒ In△ABC,tan45
o
=
BC
AB
⇒ 1=
x
7+h
⇒ x=7+h
⇒
3
h=7+h [ From ( 1 ) ]
⇒
3
h−h=7
⇒ (
3
−1)h=7
⇒ h=
3
−1
7
⇒ h=
3
−1
7
×
3
+1
3
+1
∴ h=
3−1
7(
3
+1)
=
2
7(1.73+1)
=9.55m
∴ Height of the tower is 9.55m.
Step-by-step explanation:
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Answered by
0
Let the height of tower be h
and the distance between the foot of tower to the point of sigh be x
[ previous solution is in the attachment ]
√3 ( 3h - h ) = 7√3
2h = 7√3/√3
2h = 7
h = 7/2
h = 3.5 m
Height of tower is 3.5m
Attachments:
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