Question

A vertical tower stands on a horizontal plane and is surmounted by a flagstaff of height 5m at a point on the plain angle of elevation at the bottom and top of flag is 45 and 60 find height of tower​

Answer 1

Answer:

In △CBD,tan30

o

=

BC

BD

⇒

3

1

=

x

h

⇒ x=

3

h ----- ( 1 )

⇒ In△ABC,tan45

o

=

BC

AB

⇒ 1=

x

7+h

⇒ x=7+h

⇒

3

h=7+h [ From ( 1 ) ]

⇒

3

h−h=7

⇒ (

3

−1)h=7

⇒ h=

3

−1

7

⇒ h=

3

−1

7

×

3

+1

3

+1

∴ h=

3−1

7(

3

+1)

=

2

7(1.73+1)

=9.55m

∴ Height of the tower is 9.55

Answer 2

Step-by-step explanation:

first of all we took

tan45=h/x

1=h/x

h=x.....(1)

now

tan60=h+5/x

root 3=h+5/x

and then put x=h from eq 1..

and solve it.