a vertical tower stands on a horizontal plane and is surmounted by a flagstaff of height of 30m.at a point on the plane,the angke of elevation of the bottom of a Flagstaff is 45° and that of top it is 60° .determine the height of the tower and the horizontal distance
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Distance between point of observation and foot of tower = 20 m = BC
Angle of elevation of top of tower = 60∘=Θ
Height of tower H = AB
Now from fig ABC
ΔABC is a right angle triangle
1tanΘ=oppositeside(AB)Adjacentside(BC)
i.e tanC=ABBC
AB = 20 tan60∘
H = 20×3–√
= 203–√
∴heightofthetower=203–√m
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