Question

A vertical tower subtends an angle 60°at a point on the same level as the foot of the tower.on on moving 100m further from the first point in line with the tower,it subtends an angle 30°at the point.find the height of the tower​

Answer 1

Answer:

I wish you will understand

Answer 2

The height of the tower is 50$\sqrt{3}$m.

Step-by-step explanation:

Let the height of the tower be AD and the B be a point x metres away.

Now, in ΔDAB:

Tan60= AD÷x

Tan60= H÷x

So, H=  x$\sqrt{3}$-----(1)

Now, let point C be x+100 metres away from the tower,

Then tan30= H÷(x+100)

From equation1, putting the value of H

1 ÷$\sqrt{3}$ =  x$\sqrt{3}$ ÷ (x+100)

1= 3x ÷(x+100)

(x+100)= 3x

100=  2x

x= 50m

Now, putting the value of x in equation 1:

H= 50$\sqrt{3}$m

Result:

The height of the tower is 50$\sqrt{3}$m.

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