A vertical tree is broken by the wind at a height of 6m from its foot and its top touches
the ground at a distance of 8 cm from the foot of tree. Calculate the distance between
the top of the tree before breaking and the point at which the tree touches the ground
after break
Answers
Answered by
1
Answer:
Let x be the length of broken part.
Total height of tree =x+6 m
Distance between foot of tree and the point where the tree touch the ground =8 m
In triangle BCD
BD
2
=BC
2
+CD
2
Using Pythagoras theorem
(Hypotenuse)
2
=(Base)
2
+(Perpendicularside)
2
x
2
=6
2
+8
2
=36+64=100
x=
100
=10 m
Total height of tree =x+6=10+6=16 m
In triangle ACD
AD
2
=AC
2
+CD
2
Substitute the values
AD
2
=(16)
2
+8
2
AD
2
=256+64
AD
2
=320
AD=
320
=8
5
m
Hence, the distance between the top and the point where the tree touches the ground =8
5
m
Similar questions