Question

A verticle pole of length 6m casts a shadow 4m long on the ground and the same time a tower vasts a Shadow 28m long . Find the height of the tower ????

If ∆ABC and ∆DEF ~ to each other
=> AB/DE = BC/EF
6m/DE =4m/28m
4DE=168m
DE= 168/4
DE= 42m
Hence, the height of tower is 42m.

Tell me fast . Am I right ????
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Answer 1

Answer:

yes

Step-by-step explanation:

you are correct and your answer is correct.