Question

★ A very simple question!

The sides of a rectangle are :
i) 5cm and 3 cm
ii) 3 cm and 6 cm
iii) 8 cm and 7 cm
iv) 7 cm and 9 cm
v) 4 cm and 9 mm
vi) 15 cm and 9 cm

Find the perimeter in all the above parts(i - vi)..

[Please take care of the units]
​

Answer 1

Answer:

i)16cm

ii)18cm

iii)30cm

iv)32cm

v)26cm

vi)48cm

Step-by-step explanation:

Hope it helps.

Answer 2

Given :-

The sides of a rectangle

To find :-

The perimeter

Using Formula :-

${\underline{\boxed{{\sf{Perimeter {\small_{(Rectangle)}} = \underline{\underline{\boxed{\purple{\sf 2(Side 1 + Side 2)}}}}}}}}}$

Let's start :-

i) 5cm and 3 cm

Diagram :-

$\begin{gathered}\begin{gathered} \begin{gathered} \sf{ \blue{3 \: cm }\:}\huge\boxed{ \begin{array}{cc} \: \: \: \sf\footnotesize{For \: part (i) \: \: \: }\\ \: \: \: \end{array}} \\ \: \: \: \: \: \sf{ \blue{5 \: c m}}\end{gathered} \end{gathered} \end{gathered}$

We know ,

${\underline{\boxed{{\sf{Perimeter {\small_{(Rectangle)}} = \underline{\underline{\boxed{\blue{\sf 2(Side 1 + Side 2)}}}}}}}}}$

Putting , Side 1 as 3cm and Side 2 as 5cm

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 2(3cm + 5cm)$

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 2(8cm)$

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 16cm$

ii) 3 cm and 6 cm

Diagram :-

$\begin{gathered}\begin{gathered} \begin{gathered} \sf{ \purple{6 \: cm }\:}\huge\boxed{ \begin{array}{cc} \: \: \: \sf\footnotesize{For \: part (ii) \: \: \: }\\ \: \: \: \end{array}} \\ \: \: \: \: \: \sf{ \purple{3 \: c m}}\end{gathered} \end{gathered} \end{gathered}$

We know ,

${\underline{\boxed{{\sf{Perimeter {\small_{(Rectangle)}} = \underline{\underline{\boxed{\purple{\sf 2(Side 1 + Side 2)}}}}}}}}}$

Putting , Side 1 as 6cm and Side 2 as 3cm

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 2(6cm + 3cm)$

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 2(9cm)$

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 18cm$

iii) 8 cm and 7 cm

Diagram :-

$\begin{gathered}\begin{gathered} \begin{gathered} \sf{ \green{7 \: cm }\:}\huge\boxed{ \begin{array}{cc} \: \: \: \sf\footnotesize{For \: part (iii) \: \: \: }\\ \: \: \: \end{array}} \\ \: \: \: \: \: \sf{ \green{8 \: c m}}\end{gathered} \end{gathered} \end{gathered}$

We know ,

${\underline{\boxed{{\sf{Perimeter {\small_{(Rectangle)}} = \underline{\underline{\boxed{\green{\sf 2(Side 1 + Side 2)}}}}}}}}}$

Putting , Side 1 as 7cm and Side 2 as 8cm

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 2(7cm + 8cm)$

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 2(15cm)$

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 30cm$

iv) 7 cm and 9 cm

Diagram :-

$\begin{gathered}\begin{gathered} \begin{gathered} \sf{ \orange{9 \: cm }\:}\huge\boxed{ \begin{array}{cc} \: \: \: \sf\footnotesize{For \: part (iv) \: \: \: }\\ \: \: \: \end{array}} \\ \: \: \: \: \: \sf{ \orange{7 \: c m}}\end{gathered} \end{gathered} \end{gathered}$

We know ,

${\underline{\boxed{{\sf{Perimeter {\small_{(Rectangle)}} = \underline{\underline{\boxed{\orange{\sf 2(Side 1 + Side 2)}}}}}}}}}$

Putting , Side 1 as 9cm and Side 2 as 7cm

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 2(9cm + 7cm)$

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 2(16cm)$

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 32cm$

v) 4 cm and 9 mm

In this part we will convert 9mm into cm , So let's do it!!!

As we know that

$\longrightarrow \sf 1mm = \dfrac{1}{10} cm$

Therefore , For 9mm

$\longrightarrow \sf\dfrac{9}{10} cm$

$\longrightarrow \sf 0.9cm$

Diagram :-

$\begin{gathered}\begin{gathered} \begin{gathered} \sf{ \red{0.9\: cm }\:}\huge\boxed{ \begin{array}{cc} \: \sf\footnotesize{For \: part (v) \: \: \: }\\ \end{array}} \\ \sf{ \red{4 \: c m}}\end{gathered} \end{gathered} \end{gathered}$

We know ,

${\underline{\boxed{{\sf{Perimeter {\small_{(Rectangle)}} = \underline{\underline{\boxed{\red{\sf 2(Side 1 + Side 2)}}}}}}}}}$

Putting , Side 1 as 4cm and Side 2 as 0.9cm

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 2(4cm + 0.9cm)$

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 2(4.9cm)$

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 9.8cm$

vi) 15 cm and 9 cm

Diagram :-

$\begin{gathered}\begin{gathered} \begin{gathered} \sf{ \pink{9 \: cm }\:}\huge\boxed{ \begin{array}{cc} \: \: \: \sf\footnotesize{For \: part (vi) \: \: \: }\\ \: \: \: \end{array}} \\ \: \: \: \: \: \sf{ \pink{15 \: c m}}\end{gathered} \end{gathered} \end{gathered}$

We know ,

${\underline{\boxed{{\sf{Perimeter {\small_{(Rectangle)}} = \underline{\underline{\boxed{\pink{\sf 2(Side 1 + Side 2)}}}}}}}}}$

Putting , Side 1 as 9cm and Side 2 as 15cm

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 2(9cm + 15cm)$

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 2(24cm)$

$\longrightarrow \sf Perimeter{\small_{(rectangle)}} = 48cm$

$\begin{gathered} \\ {\underline{\rule{300pt}{2pt}}} \end{gathered}$

The Answers are :-

(i) 16cm

(ii) 18cm

(iii) 30cm

(iv) 32cm

(v) 9.8cm

(vi) 48cm