Question

A very small particle of mass m and charge q is given an initial speed u
against uniform electric field E. How much distance will the particle cover
before acquiring the same speed again?​

Answer 1

Answer:

u*t is u r answer for u r question

Answer 2

Answer:

Given

u=Velocity of projection,  

E

=Electric field intensity

q= charge on the particle

m= mass of particle

We know, Force experienced by a particle with charge 'q' in an electric field  

E

=qE

∴ the acceleration produced is given as:

a=  

m

qE

​  

.

As the particle is projected against the electric field, hence deceleration =  

m

qE

​  

 

So, let the distance covered be 's'

Then, v  

2

=u  

2

+2as  

[where a=acceleration, v=final velocity]

0=u  

2

−2×  

m

qE

​  

×S

⇒S=  

2qE

u  

2

m

​  

 units.

Answer By

Amit