Question

A vessel A contains a mixture of X milliliters of milk
and water conta
ining 40% water. Pot B also has a
mixture of milk and water that contains 20% water.
There is two times the amount of mixture in pot B.If
the mixture of pot B is completely mixed in the
mixture of pot A, and the resulting mixture of pot A
contains 198 ml of milk, what is the value of x.
(b) 90
(d) 95
(a) 45
(C) 85​

Answer 1

Step-by-step explanation:

Without using x solution

Explanation-

Mixture given = 40L

10% of which was water. So remaining 90% was milk.

Now we have to increase the water percentage to 20%. Therefore the milk percentage in new mixture is 80%. In ratio, it becomes 4:1.

Lets say we added ‘x’ litres of water in the mixture and quantity of milk remains constant throughout.

So, x=5L of water must be added in the mixture to make water 20% in new mixture.

Answer 2

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