Question

A vessel contain 4 black beads ,6 white beadsand 10 red beads . In another vessel Contain 7 black beads ,5 white beads and 8 red beads . If we take one beads from each vessel without looking into it?
a. What is the probability of both being same color ?
b. What is the probability of both being different colourC. What is the probability of getting atleast one black beads?​

Answer 1

Answer:

First box contains 8 black and 12 white beads Second box contains 9 black and 6 white beads.

(a) One black bead from each box is taken.

Number of such cases = 8×9=72

Total number of possibilities = 20×15=300

Probablity of getting both black beads =

300

72

=

25

6

(b) One black and one white bead is taken.

So if one black bead is taken from first box then one white bead is taken from second box and if one white bead is taken from first box then one black bead is taken from second box.

Number of such cases = 8×6+12×9=48+108=156

Total number of possibilities = 20×15=300

Probablity of getting one black and one white bead =

300

156

=

25

13