Question

A vessel contain equal masses of Hydrohen and Helium. The fraction of the partial preesure of Hydrogen

Answer 1

Answer:

my answer is 2/3

I hope it is helpful to you

Answer 2

Answer:

Partial pressure of hydrogen gas is two-thirds of total pressure of mixture.

Partial pressure of helium is one-third of total pressure.

Explanation:

Consider the mass of hydrogen and helium is equal to m.

The number of moles of hydrogen gas, $n_{a}=\frac{m}{2}$

The number of moles of helium gas, $n_{b}=\frac{m}{4}$

The mole fraction of hydrogen gas, $x_{a}=\frac{n_{a}}{n_{a}+n_{b}}$

$x_{a}=\frac{\frac{m}{2} }{\frac{m}{2}+\frac{m}{4} }$

$x_{a}=\frac{2}{3}$

the mole fraction of helium gas, $x_{b}=\frac{n_{b}}{n_{a}+n_{b}}$

$x_{b}=\frac{\frac{m}{4} }{\frac{m}{2}+\frac{m}{4} }$

$x_{b}=\frac{1}{3}$

Partial pressure of a component = (Total pressure)× (mole fraction of that component)

$p_{H_{2}}=P_{t}*\frac{2}{3} }=\frac{2P_{t}}{3}$

$p_{(He)}=P_{t}*\frac{1}{3}=\frac{P_{t}}{3}$

where, $P_{t$ is the total pressure of the mixture.