a vessel containing 44.8 lit helium and 67.2 lit hydrogen at stp calculate the weight of new mixture
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44.8 ×(1/22.4)×(4/1)= weight of 44.8litres of helium.=> 8 gms
67.2× (1/22.4)×(4/1)= weight of 67.2 litres of hydrogen. =>12gms
total mixture =8+12=> 20gms
vishwacharan2018:
how is that possible
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