a vessel contains 1 mol of oxygen and 2 mol of helium what is the mixture of Cp/Cv of the mixture
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Hi friend,
resulting Cp/Cv=n1Cp1+n2Cp2/n1Cv1+n2Cp2
here n1=1 and Cp1 =7/2R Cv1=5/2R
n2=2 and Cp2=5/2Rand Cv2=3/2R
now,substituting values in above formula we get resulting Cp/Cv=17/11≈1.545.
Hope this helps you.......
resulting Cp/Cv=n1Cp1+n2Cp2/n1Cv1+n2Cp2
here n1=1 and Cp1 =7/2R Cv1=5/2R
n2=2 and Cp2=5/2Rand Cv2=3/2R
now,substituting values in above formula we get resulting Cp/Cv=17/11≈1.545.
Hope this helps you.......
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