A vessel contains 100 liters mixture of
milk and water in the respective ratio of
22 : 3. 40 liters of the mixture is taken
out from the vessel and 4.8 litters of
pure milk and pure water each is added
to the mixture. By what percent is the
quantity of water in the final mixture less
than the quantity of milk?
Answers
Answered by
0
Answer: MARK AS BRAINLIEST AND FOLLOW ME
Step-by-step explanation:
Remaining mixture in the vessel = 60 litres
Milk = 2225×60 = 52.8 litres
Water = 7.2 litres
On adding additional milk and water.
Milk = 52.8 + 4.8 = 57.6 litres
Water = 7.2 + 4.8 = 12 litres
Therefore, Required percent = 57.6−1257.6×100
=45.657.6×100
=4756=7916
Similar questions