A vessel contains 100 litre of a liquid X heat is supplied to the liquid in such a fashion that heat given is equal to change in enthalpy the volume of liquid increases by 2 litres if external pressure is 1 ATM and 202.6 joules of heat was supplied then u-> total internal energy
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Answer:
Based on given data we already know
Q=ΔH
Here ΔH=+202.6
workdone in expansion=-PΔV
=-1(2)L.atm
=-2*101.325joules
=-202.6J
so based on first law of thermodynamics we get
ΔE=Q+W=0
finally we get ΔU=0 and ΔH=+202.6J
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