Question

A vessel contains 110g of water the heat capacity of vessel is equal to 10g of water the initial temperatureof water in vessel is 10



c. If 220g of hot water at 70 c is poured into vessel the final temperatureneglecting radiation loss will be

Answer 1

Answer:

48.8°C

Explanation:

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Answer 2

final temperature of the mixture approximately equal to 50°C.

heat lost by water of temperature 70° = heat gained by water of temperature 10°C

let final temperature of mixture is T.

⇒m1s(T1 - T) = m2s(T - T2)

here, m1 = 220g, T1 = 70°C, T2 = 10°C , m2 = 110g + 10g = 120g

⇒220 × s (70 - T) = 120 × s (T - 10)

⇒22(70 - T) = 12(T - 10)

⇒1540 - 22T = 12T - 120

⇒1660 = 34T

⇒T = 48.82°C ≈ 50°C

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