Question

A vessel contains 180 litres of milk, 60 litres are taken out of the vessel everyday & equal quantity of water is added. what quantity of milk remains in the vessel at the end of 3 days.

Answer 1

this can be done as x(1-y/x)^n where x is the total amt present and y is the amt successively withdrawn from the vessel and n is the no of times i.e 3
therefore, 180(1-60/180)^3 = 160/3 = 53.33

Answer 2

Answer:

53.33 liters ( approx )

Step-by-step explanation:

The formula of the quantity of pure liquid is,

$Q=x(1-\frac{y}{x})^n$

Where,

x = initial quantity of pure liquid,

y = quantity of pure liquid replaced by other liquid,

n = number of times,

Here,

x = 180 liters,

y = 60 liters,

n = 3,

Thus, the quantity of milk remains in the vessel at the end of 3 days,

$Q=180(1-\frac{60}{180})^3=180(1-1/3)^3=180(2/3)^3=\frac{1440}{27}\approx 53.33\text{ liters}$