Math, asked by 1815013, 11 months ago

A vessel contains 24 litres of milk, 4 litres are withdrawn and replaced by water. The process is repeated a second time. Find the ratio of milk to water in the resulting mixture?

Answers

Answered by vj7
4

Answer:25:11

Step-by-step explanation:

volume of milk left=initial volume of milk(1-x/v)^n

initial volume of milk=24 litres=volume of vessel

x=4 litres ; n=2 times

volume of milk left =24(1-(4/24))^2

                               =50/3

ratio of milk to water =(50/3)/(24-(50/3))

                                   =50/22

                                   = 25/11

Answered by Dhruv4886
0

Answer:

Step-by-step explanation:

As given:

Vessel contains milk  (x)           = 24 Litres

Quantity of milk taken out (y) = 4 Litres     (Replaced by water)

After n operations, the quantity of pure liquid = [x 〖(1- y/x)〗^n ] units.

After 2 operations, the quantity of pure liquid = [24 〖(1- 4/24)〗^2 ] units.

                                  the quantity of pure liquid = [24 × 20/24×20/24] units.

                                  the quantity of pure liquid = 16.66 units.

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