Question

A vessel contains 5.6 grams of N, gas. Calculate the number of moles of N2 gas, number of nitrogen molecules and the number of nitrogen atoms, if the atomic mass of N is 14.0u​

Answer 1

Explanation:

Given that

Given that5.6g of nitrogen

Given that5.6g of nitrogenAtomic mass of nitrogen = 14u

Given that5.6g of nitrogenAtomic mass of nitrogen = 14uWe know that,

Given that5.6g of nitrogenAtomic mass of nitrogen = 14uWe know that,Molar atomic mass of nitrogen = 14g mol-1

Given that5.6g of nitrogenAtomic mass of nitrogen = 14uWe know that,Molar atomic mass of nitrogen = 14g mol-1Molar mass of N2 = 2 x 14g mol-1 = 28g mol-1

Given that5.6g of nitrogenAtomic mass of nitrogen = 14uWe know that,Molar atomic mass of nitrogen = 14g mol-1Molar mass of N2 = 2 x 14g mol-1 = 28g mol-1a) No.of moles of N2 in 5.6g of nitrogen

Given that5.6g of nitrogenAtomic mass of nitrogen = 14uWe know that,Molar atomic mass of nitrogen = 14g mol-1Molar mass of N2 = 2 x 14g mol-1 = 28g mol-1a) No.of moles of N2 in 5.6g of nitrogen= 5.6g/28g mol-1

Given that5.6g of nitrogenAtomic mass of nitrogen = 14uWe know that,Molar atomic mass of nitrogen = 14g mol-1Molar mass of N2 = 2 x 14g mol-1 = 28g mol-1a) No.of moles of N2 in 5.6g of nitrogen= 5.6g/28g mol-1=0.2 mol

Given that5.6g of nitrogenAtomic mass of nitrogen = 14uWe know that,Molar atomic mass of nitrogen = 14g mol-1Molar mass of N2 = 2 x 14g mol-1 = 28g mol-1a) No.of moles of N2 in 5.6g of nitrogen= 5.6g/28g mol-1=0.2 molb) No.of molecules of N2 in 5.6g of nitrogen

Given that5.6g of nitrogenAtomic mass of nitrogen = 14uWe know that,Molar atomic mass of nitrogen = 14g mol-1Molar mass of N2 = 2 x 14g mol-1 = 28g mol-1a) No.of moles of N2 in 5.6g of nitrogen= 5.6g/28g mol-1=0.2 molb) No.of molecules of N2 in 5.6g of nitrogen= 6.023 x 1023 x no.of moles of N2

Given that5.6g of nitrogenAtomic mass of nitrogen = 14uWe know that,Molar atomic mass of nitrogen = 14g mol-1Molar mass of N2 = 2 x 14g mol-1 = 28g mol-1a) No.of moles of N2 in 5.6g of nitrogen= 5.6g/28g mol-1=0.2 molb) No.of molecules of N2 in 5.6g of nitrogen= 6.023 x 1023 x no.of moles of N2= 6.023 x 1023 x 0.2

Given that5.6g of nitrogenAtomic mass of nitrogen = 14uWe know that,Molar atomic mass of nitrogen = 14g mol-1Molar mass of N2 = 2 x 14g mol-1 = 28g mol-1a) No.of moles of N2 in 5.6g of nitrogen= 5.6g/28g mol-1=0.2 molb) No.of molecules of N2 in 5.6g of nitrogen= 6.023 x 1023 x no.of moles of N2= 6.023 x 1023 x 0.2= 1.2 x 1023

Given that5.6g of nitrogenAtomic mass of nitrogen = 14uWe know that,Molar atomic mass of nitrogen = 14g mol-1Molar mass of N2 = 2 x 14g mol-1 = 28g mol-1a) No.of moles of N2 in 5.6g of nitrogen= 5.6g/28g mol-1=0.2 molb) No.of molecules of N2 in 5.6g of nitrogen= 6.023 x 1023 x no.of moles of N2= 6.023 x 1023 x 0.2= 1.2 x 1023c) One molecule of N2 has two N atoms

Given that5.6g of nitrogenAtomic mass of nitrogen = 14uWe know that,Molar atomic mass of nitrogen = 14g mol-1Molar mass of N2 = 2 x 14g mol-1 = 28g mol-1a) No.of moles of N2 in 5.6g of nitrogen= 5.6g/28g mol-1=0.2 molb) No.of molecules of N2 in 5.6g of nitrogen= 6.023 x 1023 x no.of moles of N2= 6.023 x 1023 x 0.2= 1.2 x 1023c) One molecule of N2 has two N atomsNo of atoms of nitrogen

Given that5.6g of nitrogenAtomic mass of nitrogen = 14uWe know that,Molar atomic mass of nitrogen = 14g mol-1Molar mass of N2 = 2 x 14g mol-1 = 28g mol-1a) No.of moles of N2 in 5.6g of nitrogen= 5.6g/28g mol-1=0.2 molb) No.of molecules of N2 in 5.6g of nitrogen= 6.023 x 1023 x no.of moles of N2= 6.023 x 1023 x 0.2= 1.2 x 1023c) One molecule of N2 has two N atomsNo of atoms of nitrogen= 2 x no.of N2 molecules

Given that5.6g of nitrogenAtomic mass of nitrogen = 14uWe know that,Molar atomic mass of nitrogen = 14g mol-1Molar mass of N2 = 2 x 14g mol-1 = 28g mol-1a) No.of moles of N2 in 5.6g of nitrogen= 5.6g/28g mol-1=0.2 molb) No.of molecules of N2 in 5.6g of nitrogen= 6.023 x 1023 x no.of moles of N2= 6.023 x 1023 x 0.2= 1.2 x 1023c) One molecule of N2 has two N atomsNo of atoms of nitrogen= 2 x no.of N2 molecules= 2 x 1.2 x 1023

Given that5.6g of nitrogenAtomic mass of nitrogen = 14uWe know that,Molar atomic mass of nitrogen = 14g mol-1Molar mass of N2 = 2 x 14g mol-1 = 28g mol-1a) No.of moles of N2 in 5.6g of nitrogen= 5.6g/28g mol-1=0.2 molb) No.of molecules of N2 in 5.6g of nitrogen= 6.023 x 1023 x no.of moles of N2= 6.023 x 1023 x 0.2= 1.2 x 1023c) One molecule of N2 has two N atomsNo of atoms of nitrogen= 2 x no.of N2 molecules= 2 x 1.2 x 1023= 2.4 x 1023

=2455.2

Answer 2

Explanation:

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