Question

A vessel contains 50 litres of milk a milkman take 6 liters of milk and replace it with water if the mikkman repeat the same process twice how much milk is left

Answer 1

Answer:

Initially, milk in the container = 50 Litres

Water in the container = 0 L

On removing 5L milk and adding same amount of water,

Milk in the container = 45 L

Water in the container = 5 L

I hope, upto here, it's clear. When again same process is done, 5 L of the solution has been taken out ( We can't say 5L milk will be taken out because that has become a solution now). So if 50 L solution has 45L milk and 5 L water, 5 L solution will have 4.5L milk and 0.5L water

So now, milk in the container = 45–4.5 = 40.5 L

Water in the container = 5–0.5+5 = 9.5 L

The sum of volumes of milk and water should be always 50 L

Now the final time, same thing has been done

Milk in the container = 40.5 - 4.05 = 36.45 L

Water in the container = 9.5 - 0.95 + 5 = 13.55 L

So, the answer to the question that has been asked here is 36.45 Litres of Milk will be there in that container

Step-by-step explanation:

you have to do like this

hope u like it

mark me brainlist

thank you ☺️☺️