A vessel contains 56 litres of mixture of milk and water in the ratio 5:2. how much water should be mixed with it so tat the ratio of mil to water is 4:5
Answers
Answered by
1
Initially, the mixture is 7 parts. The final mixture can be understood of 9 parts, although
the parts will become different size.
The concentration of milk at the start is 5/7, and concentration of milk wanted is 4/9.
Simple two-part mixture problem.
Let x be how many parts milk to add to the start mixture.
56 * (5/7) + x/ (x + 56) = 4/9
(40 + x) / (x + 56) = 4/9
9 * (40 + x) = 4 * (x + 56)
360 + 9x = 4x + 224
9x - 4x = 224 - 360
5x = 136
x = 136/5
x = 27.2 litres
the answer is 27.2 litres.
Hope This helps :)
the parts will become different size.
The concentration of milk at the start is 5/7, and concentration of milk wanted is 4/9.
Simple two-part mixture problem.
Let x be how many parts milk to add to the start mixture.
56 * (5/7) + x/ (x + 56) = 4/9
(40 + x) / (x + 56) = 4/9
9 * (40 + x) = 4 * (x + 56)
360 + 9x = 4x + 224
9x - 4x = 224 - 360
5x = 136
x = 136/5
x = 27.2 litres
the answer is 27.2 litres.
Hope This helps :)
Answered by
0
Step-by-step explanation:
correct answer
Similar questions