Question

 A Vessel contains 60 litres of milk, 6 litres of milk is taken out and 6 litres of
water is added to the vessel. Again 6 litres of milk from the vessel is withdrawn
and 6 litres of water is added to the vessel. The ratio of milk and water in the
resulting mixture in the vessel is
1) 81 : 19 2) 71 : 29 3) 61 : 39

Answer 1

Hi ,

We know that ,

Suppose a container

contains M units of

Mixture of ' X ' and ' Y '

from this , R unit of

mixture is drawn off and

replaced by an equal

amount of

ingradient Y only. The

process is repeated ' n '

times , then after ' n '

repetetions.

( Amount of X left ) / (Amount of X originally present )

= ( 1 - R / M )^n

According to the problem given,

M = 60 liters

R = 6 liters

n = 2 times

( Amount of milk left )/60 =

( 1 - 6/60)²

Amount of milk left = 60×(1 - 1/10)²

= 60× ( 9/10)²

= 60 × 9/10 × 9/10

= 48.6 liters

Amount of water = 60 - 48.6

= 11.4 liters

Ratio = 48.6 : 11.4

= 486 : 114

Divide it with 6

= ( 486 / 6 ) : ( 114 / 6)

= 81 : 19

Therefore,

Option 1) is correct

I hope this helps you.

:)

Answer 2

Answer:

option 1 is correct 81:19