Question

a vessel contains 90 litres of a mixture of alchohol(at a concentration of 80% by volume) and water.20 liters of the mixture is taken out and x liters of water is added.As a result,the concentration of alcohol(by volume)in the mixture become 70%,find x
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Answer 1

Answer:

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Mixture = 70 L

==>> Water =10% of mixture = 10% of 70 = 7 L.

==>> Alcohol = 63 L.

==>> Let x water added. Now, Water and Alcohol ratio will be,

=> (7 + x)/63 = 12.5/87.5

=> 7 +x = 787.5/87.5

=> 7 + x = 9

===>> x = 2 L.

$\huge\sf\boxed{\red{Water added = 2 L }}$

Answer 2

Answer:

• Mixture = 70 L
• Water =10% of mixture = 10% of 70 = 7 L.
• Alcohol = 63 L.
• Let x water added. Now, Water and Alcohol ratio will be,
• (7 + x)/63 = 12.5/87.5
• 7 +x = 787.5/87.5
• 7 + x = 9
• x = 2 L.
• Water added = 2 L.