Question

A vessel contains A(g) and B(g) at 2 atm and 4 atm respectively at TK, the mixture is
allowed to attain the equilibrium at TK, according to the reaction
8B(8)=8A(g)+C($)
na ) initial
At the equilibrium,
Find the value of y if K = 2y
.​

Answer 1

Concept Introduction: Equilibrium is studied in advanced chemistry.

Given:

We have been Given: 8B(g)=8A(g)+C(s)

Partial Pressures are

$a = 2 \: atm \\ b = 4 \: atm \\ c = 0 \: atm$

since C is a solid so no pressure.

$k = 2y$

To Find:

We have to Find: The value of

$y$

Solution:

According to the problem, Putting the values, we get,

$k = \frac{ {(b)}^{8} }{ {(a)}^{8} + c} \\ 2y= \frac{ {(4)}^{8} }{ {(2)}^{8} + 0} \\ 2y = \frac{65536}{256} \\ 2y = 256 \\ y = \frac{256}{2} \\ y = 128$

Final Answer: The value of

$y = 128$

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Answer 2

Concept introduction:

Chemical equilibrium refers to the situation in a chemical process where both the reagents are capable of accumulating that have no more inclination to vary over time, preventing any discernible change in the system's characteristics.

Given:

Here it is given that $8B(g)=8A(g)+C(s)$

$a=2atm,b=4atm$.

$K = 2y$.

To find:

We have to find the value of $y$.

Solution:

According to the problem, by putting the given values in the equation we get,=>    $k=\frac{b^{8} }{a^{8} +c}$

        $= > 2y=\frac{4^{8} }{2^{8}+0 }$

Here $C=0$ because it is in solid state so there is no pressure.

So,  

$2y=256\\y=128$

So, the value of $y$ is $128$.

Final answer:

Hence, the final answer of the question is -> $128$.

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