A vessel contains a mixture of 160L of milk
and 20L of water. Then 'x' L of mixture is
taken out and 20L of milk and 25L of water
are added to the remaining mixture. If the
difference between the quantity of milk and
water is 100 1tr, then find 'x'?
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Answer:
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Answer:
Qty.of milk in the mixture= (11/14)160= 880/7 lit.
Qty of water in the mixture = (3/14)×160=240/7 lit
Qty.of milk in 34 litres of mixture= (11/14)34 = 187/7 lit.
Qty.of water in the 34 litres of mixture=(3/14)34 = 51/7 lit
Qty.of remaining milk in the mixture = 880/7 - 187/7 = 693/7 lit= 99 lit
Qty.of water in the remaining mixture= 240/7 - 51/7 = 189/7 = 27 lit.
Qty.of water in the remaining mixture after adding 4 lit.of water = 27+4 = 31 lit
Now the ratio of milk and water in the mixture = 99:31 = 3:1 approximately
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