A vessel contains a mixture of 7 gm of nitrogen and 11 gm of carbon dioxide at room temprature t = 290k. if the pressure of the mixture p = 1 atm, calculate the its density
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Answered by
6
Density = mass/volume
mass=7+11=18
the value of volume is calculated from equation PV=nRT
Volume=119
Density=18/119=0.15
mass=7+11=18
the value of volume is calculated from equation PV=nRT
Volume=119
Density=18/119=0.15
Answered by
2
Using the formula for gas
PM = d RT (here P = pressure, M = molecular mass of mixture, d =density of mixture, R = gas constant, T = temp)
d =PM/RT
now mass of mixture = weight / number of moles
now number of moles = moles of nitrogen +moles of carbon dioxide
= weightmolecular mass = wnmn+wcomco = 728+1144 = 14+14 = 12gramand weight of mixture = 7+11 = 18 gram
mass of mixture =
1812 = 36 gram
now equating in equation
1.01×105×36×10−38.31×290 =0.015×102=1.5kg/m3
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