Question

A vessel contains a mixture of milk and water in the respective ratio of 13 : 5. 27 litres of the mixture is taken out from the vessel and 4.5 litres of each pure milk and pure water is added to the mixture. if the resultant mixture contains 30% water, what was the initial quantity of mixture in the vessel before the replacement ? (in litres)

Answer 1

Initial the mixture contains 14x litres of milk and 3x litres of water from this we take 25.5 litres(17x-25.5) and add 2.5 litres of water and 5 litres of milk the resultant mixture is (17x -25.5 +7.5) now taking 25.5 litres from the initial mixture means taking out 3/17x25.5 litres of milk so we have taken out 4.5 litres of milk and added 2.5 litres of milk, the resultant mixture contains 3x-4.5+2.5 litres of milk which is equal to 20 percent of (17x-25.5+7.5) of the new mixture now solving this we get the value of x (((17x-25.5 +7.5)x(20/100))=(3x-4.5+2.5))==>x=4 the ;hence the initial quantity of mixture is 17x4=68