Question

a vessel contains a mixture of one mole of oxygen and two moles of nitrogen at 300K. find the ratio of average rotational kinetic energies per O2 molecule to per N2 molecule.​

Answer 1

Answer:

The ratio of the rotational kinetic energy of both the gases is 1:1.

Kinetic energy per degree of freedom = 1/2 kT

Since both Oxygen and nitrogen are diatomic gases and diatomic gas possess two degree of freedom for rotational motion therefore ,

rotational   K.E. = 2(1/2kT) = kT

In the problem both gases (oxygen and nitrogen) are diatomic and have same temperature (300 K) therefore ratio of average rotational kinetic energy will be equal to one.

Hope it helps you