A vessel contains a mixture of one mole of oxygen and two moles of nitrogen at 300 k. Then the ratio of average rotational kinetic energies per o2 molecule to per n2 molecule is
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The ratio of the rotational kinetic energy of both the gases is 1:1.
Explanation:
Kinetic energy per degree of freedom = 1/2 kT
Since both Oxygen and nitrogen are diatomic gases and diatomic gas possess two degree of freedom for rotational motion therefore ,
rotational K.E. = 2(1/2kT) = kT
In the problem both gases (oxygen and nitrogen) are diatomic and have same temperature (300 K) therefore ratio of average rotational kinetic energy will be equal to one.
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