A vessel contains equal masses of hydrogen and helium. The fraction of the partial pressure of hydrogen in the mixture is
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Partial pressure of hydrogen in the mixture is 0.67 of the total pressure.
Explanation:
- Let the mass of He and H be x.
- Number of moles of H(n₁) will be x/2(0.5x) and of He(n₂) will be x/4(0.25x).
- Let the total pressure of container be P. The partial pressure of any gas is given by its mole fraction multiplied into total pressure.
- Thus partial pressure of hydrogen, P₁ will be given be n'P, where n' is mole fraction of hydrogen.
P₁ = n' P
P₁ = (n₁/n₁+n₂)P
P₁ = (0.5x/0.5x+0.25x)P = (0.5x/0.75x)P
P₁ = 0.67P
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