Chemistry, asked by Anonymous, 11 months ago

A vessel contains H2O(liquid), H2O(vapour), O2(gas). Vapour pressure of H2O is 300 torr and total pressure is 600 torr. Now the volume of the container reduce to the half. Find the new total pressure in the container.​

Answers

Answered by s02371joshuaprince47
0

Answer:

All conditions except the pressure and volume are fixed, so P1V1 = P2V2 can be used: ... 5.30 The ideal gas equation, PV = nRT, can be used to calculate moles using ... mol 1. = 3.00 mol;. V = 3.00 L;. T = 27 + 273 = 300 K; torr. 10 x 87.1 atm 1 torr ... water vapor: (a) Pfinal = 756 torr – 31.824 torr = 724 torr;. (b) X(H2O) = total.

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