Question

A vessel contains liquid a and b in the ratio of 5:3 .If the 16 litres of the mixture is removed and the same quantity of litres added in above the b in the ratio 3:5.What is the capacity of vessel

Answer 1

Answer:

let A is 5x and B is 3x

Step-by-step explanation:

In removed of 16 L of mixture

A removel= (5/8)×16=10L

B removel=(3/8)×16=6L

Now,as per question,16L of B is added

Hence,new content of B =3x-6+16=3x+10

New A:new B=3:5

(5x-10):(3x+10)=3:5

On solving, we get x=5

Hence,volume of vessel = 8x=40