Question

A vessel contains liquid a and b in the ratio of 5:3 .If the 16 litres of the mixture is removed and the same quantity of litres added in above the b in the ratio 3:5.What is the capacity of vessel

Answer 1

Answer:

step by step explanation

Step-by-step explanation:

Let A is 5x,and B is 3x.

In removal of 16l of mixture,

A removed=(5/8)×16=10l,

B removed=(3/8)×16=6l.

Now,as per question,16l of B is added.

Hence,new content of B=3x-6+16=3x+10.

NewA:new B=3:5

(5x-10):(3x+10)=3:5

Solving,we get X=5

Hence, volume of vessel=8x=40l

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