Question

A vessel contains milk and water in the ratio 3:2. The volume of the contents is increased by 50% by adding water to it. form this resultant solution 30 L is withrawn and then replaced with water. th

Answer 1

Answer:

Let the original volume be x.

then, quantity of milk and water,

= 3x5

and 2x5

respectively.

After adding water to it, the volume becomes 150%, the quantity of milk and water,

= 3x5

and 9x10

3x5−129x10+12=37

14(3x - 60) = 3(9x + 120)

Or, x = 80 L

Step-by-step explanation:

Let there be 5x of solution to begin with, 3x milk, 2x water.

Now, we add 50% water, Solution becomes 7.5x containing 3x milk and 4.5x water.

30L is withdrawn and replaced with water. Milk and water are in ratio 3:4.5 ie. 2:3 presently. This means out of this 30L withdrawn, These is 2 parts milk and 3 parts water. 12L Milk and 18 L water.

Basically 12L milk is replaced with water. Final equation becomes :

(3x-12)/(4.5x+12) = 3/7.

Now solve for x, Which comes out to be 16.

Original volume was 5x= 5*16 = 80L