A vessel contains milk and water in the ratio 3:4. if 7 L milk added, the ratio gets reversed. how many liters of milk should have been added to the initial mixture so that the quantity of milk and water would have been equal?
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Answer:
Let “V”- be the volume of milk-water mixture present initially.
Volume of water present is
So (V-14) x 3/7 + 14= Vx 4/7
So 3(V-14) +(14x7)= 4V
So V= 98–42= 57- LITRES
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Check:
(56–14)x 3/7 +14 =(42x 3/7)+14
=32- litres
Also
56/7 x4= 32- litres. OK.
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Step-by-step explanation:
hope that helps
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