Question

a vessel contains milk and water in the ratio of 3:2. The volume of the content is increased by 50% by adding water.From this resultant solution 30 litres is withdrawn and th en replaced with water.The resultant ratio of milk to water finally is 3:7 . find the original volume.

Answer 1

Let the original volume be x.
then, quantity of milk and water,
= 3x/5 and 2x/5 respectively.
After adding water to it, the volume becomes 150%, the quantity of milk and water,
= 3x/5 and 9x/10.
{(3x/5)-12} / {(9x/10)+12} = 3/7
14(3x-60) = 3(9x+120)
Or, x = 80 L.

More Explanation:
Ratio of milk to water = 3:2.Do we can take the volume of milk to be 3V and the volume of water to be 2V, and the total volume to be 3V + 2V = 5V.
Volume is increased by 50% by adding water. Therefore volume goes from 5V to 7.5V (an increase of 2.5V). Since only water has been added the NEW volume of water in solution is now 2V + 2.5V = 4.5V.And the new ratio of milk to water is 3:4.5
Now 30 liters are withdrawn. Since we know the new ratio we can calculate that the volume of milk withdrawn is (30/7.5)*3 = 12 liters, which means 18 liters of water have

Answer 2

Answer:

hence x = 80

the trick is knowing that water volume is increasing while milk quantity remains constant except in last replacement step