A vessel contains mixture acetone and water mixed in certain ratio. When 25 percent of the mixture is taken out and replaced with same quantity of water, then the ratio of acetone to water becomes 5:7 . Find the ratio of acetone to water, initially in the mixture.
Answers
Given : A vessel contains mixture acetone and water mixed in certain ratio. When 25 percent of the mixture is taken out and replaced with same quantity of water, then the ratio of acetone to water becomes 5:7 .
To Find : the ratio of acetone to water, initially in the mixture.
Solution:
Let say initially Acetone 4A
and Water is 4W
Ratio is 4A : 4W = A : W
=> Mixture = 4A + 4Q
25 percent of the mixture is taken out
=> Water taken out = A and Acetone Taken out = W
Water added = A + W
Acetone = 4A - A = 3A
Water = 4W - W + A + W = 4W + A
ratio of acetone to water becomes 5:7 .
=> 3A / (4W + A) = 5/7
=> 21A = 20W + 5A
=> 16A = 20W
=> 4A : 5W
=> A /W = 5/4
=> A : W = 5 : 4
ratio of acetone to water, initially in the mixture. = 5 : 4
Learn more:
In a mixture of a, b and c, if a and b are mixed in 3:5 ratio and b and ...
https://brainly.in/question/8317247
In a mixture ratio of first and second liquid is 2:3 and inanother ...
https://brainly.in/question/15078950
Two liquid containing (X and Y) mixture mixed in the ratio 2:3.X ...
https://brainly.in/question/9209918