A vessel contains mixture of 24 litre milk and 6 litre water and a second vessel contains a mixture of 15 litre milk and 10 litre water. If M litre is the sum of mixture of milk and water that should be taken from the first and the second vessel separately and kept in a third vessel so that the third vessel may contain a mixture of 25 litre of milk and 10 litre of water then find M/5.
Answers
Note:
Rather than getting a pair of linear equations in two variables and finding the values of variables, then adding and dividing by 5, I've directly taken the values logically and did the problem! Hope you'll understand.
Answer:
The value of M/5 for the given question is 7.
Explanation:
Let the three vessels be :
▶︎ Vessel₁
▶︎ Vessel₂
▶︎ Vessel₃
According to the question, for vessel₁ :
▶︎ Amount of milk = 24L
▶︎ Amount of water = 6L
Also, for vessel₂ :
▶︎ Amount of milk = 15L
▶︎ Amount of water = 10L
Now, let :
▶︎ A be amount of mixture from vessel₁
▶︎ B be amount of mixture from vessel₂
▶︎ M is the sum of the A and B
We know that, the sum of the mixture in vessel₃ , i.e, 25L of milk and 10L of water is nothing but the sum of A and B that is individually taken from the vessels.
So :
▶︎ M = A + B = Milk + water in vessel₃
▶︎ M = A + B = 25L + 10L
▶︎ M = A + B = 35L
Finally, finding M/5 :
▶︎ M/5 = 35/5
▶︎ M/5 = 7
Therefore, the value of M/5 is 7.
Answer:
A vessel contains mixture of 24 litre milk and 6 litre water and a second vessel contains a mixture of 15 litre milk and 10 litre water. If M litre is the sum of mixture of milk and water that should be taken from the first and the second vessel separately and kept in a third vessel so that the third vessel may contain a mixture of 25 litre of milk and 10 litre of water then find M/5.
Explanation: