Math, asked by ankitachakraborty154, 4 months ago

A vessel contains mixture of tin and copper in the
ratio of 2:3. Some amount of mixture is taken out and
28 gm copper is added to the remaining mixture so
that amount of copper becomes 66 3% in the new
mixture. If 12 % of initial mixture is 22.5 gm then,
find what amount of tin was taken out from the initial
mixture?
(a) 16gm (b) 14gm (c) 12gm
(d) 10gm (e) 18gm

Answers

Answered by Madankumar808103
0

Answer:

A vessel contains mixture of tin and copper in the

ratio of 2:3. Some amount of mixture is taken out and

28 gm copper is added to the remaining mixture so

that amount of copper becomes 66 3% in the new

mixture. If 12 % of initial mixture is 22.5 gm then,

find what amount of tin was taken out from the initial

mixture?

(a) 16gm (b) 14gm (c) 12gm

(d) 10gm (e) 18gm

A vessel contains mixture of tin and copper in the

ratio of 2:3. Some amount of mixture is taken out and

28 gm copper is added to the remaining mixture so

that amount of copper becomes 66 3% in the new

mixture. If 12 % of initial mixture is 22.5 gm then,

find what amount of tin was taken out from the initial

mixture?

(a) 16gm (b) 14gm (c) 12gm

(d) 10gm (e) 18gm

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