Question

A vessel contains some air at 30°C. To what temperature must it be heated so that one-third of the air is driven out ?


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Answer 1

Answer:

454.5K OR 181.5⁰C

Stpes :

T1 = (30+273)K = 303K

T1.M1= T2.M2

303K . M1 = T2. M1/3 × 2 ( as 1/3 of the air is driven out so for M2 left is M1/3 × 2)

T2 = 909÷2 = 454.5K

In celcius

454.5K- 273 = 181.5⁰

Answer 2

Answer:

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Explanation:

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