A vessel contains water to a height 1.5 m. Taking the density of water 10^3 kg m^-3,acceleration due to gravity 9.8 ms^-2 and area of base of vessel 100cm^2, calculate:(a)pressure and (b)the thrust at the base of the vessel.
Answers
Answered by
52
Answer:
- 1.47*10^4N/
- 147N
Explanation:
pressure formula hpg
h is 1.5m
p is 10^3
g is 9.8
put the formula hpg
1.5 *1000*9.8=14700pa
convert then 1.47*10^4.
Now,f=p*a.
hope helpful for you
Answered by
3
Given:
Height of the vessel= 1.5m
p = 1000
To Find:
Pressure and thrust at the base of the vessel
Solution:
P = hpg
= 1.5 × 1000 × 9.8
= 14700pa
Now, pressure = Force/acceleration
and Thurst = force = pressure× acceleration
= 14700 × 100 ×
= 147 N
Therefore, the pressure and the thurst at the base of the vessel = 147N
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