Physics, asked by swami201973, 7 months ago

A vessel contains water to a height 1.7 m. Taking the density of water 10^3 kg m^-3,acceleration due to gravity 9.8 ms^-2 and area of base of vessel 100cm^3
calculate:(a)pressure and (b)the thrust at the base of the vessel.

Answers

Answered by kashyap1629
1

Explanation:

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Answered by Anonymous
3

 \bold{(a) \: Pressure} \\  \bold{Height = 1.5m} \\  \bold{Density = 1000 kg/m³} \\  \bold{Acceleration  \: due \:  to \:  gravity  \: = \:  9.8m/s²} \\  \bold \green{Pressure \:  =  \: hpg} \\  \bold{ =  \: 1.5 \times 1000 \times 9.8} \\  \bold{ =  \: 14700 Pa} \\  \bold \red{ =  \: 1.47 \times  {10}^{4} N/m² \:  \: ....ans}

 \bold{(b) \: Thrust \: at \: the \: base \: of \: vessel} \\  \bold{Pressure \:  =  \:  \frac{force}{area} } \\  \bold \green{force \:  =  \: Pressure \times area} \\  \bold{ =  \: 1.47 \times  {10}^{4}  \times 100} \\  \bold \red{ =  \: 147 N \:  \: ....ans}

Hope it helps you...

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