Question

A vessel contains water up to a height of 1.5 m. Taking the density of water 10 3 kgm -3 ,
acceleration due to gravity 9.8 ms -2 and area of base of vessel 100 cm 2 , calculate (a) the
pressure and (b) the thrust, at the base of vessel.

Answer 1

Answer:

a. 1545Pa b. 15.45N

Explanation:

Given H=1.5m

Density D=103kg/m³

g=9.8m/s²

Pressure =1545Pa

We know that Pressure=Force/Area

1545=F/10^-2

F=15.45N

Answer 2

$\bold{(a) \: Pressure} \\ \bold{Height = 1.5m} \\ \bold{Density = 1000 kg/m³} \\ \bold{Acceleration \: due \: to \: gravity \: = \: 9.8m/s²} \\ \bold \green{Pressure \: = \: hpg} \\ \bold{ = \: 1.5 \times 1000 \times 9.8} \\ \bold{ = \: 14700 Pa} \\ \bold \red{ = \: 1.47 \times {10}^{4} N/m² \: \: ....ans}$

$\bold{(b) \: Thrust \: at \: the \: base \: of \: vessel} \\ \bold{Pressure \: = \: \frac{force}{area} } \\ \bold \green{force \: = \: Pressure \times area} \\ \bold{ = \: 1.47 \times {10}^{4} \times 100} \\ \bold \red{ = \: 147 N \: \: ....ans}$

Hope it helps you...

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