Question

A vessel contains water up to a height of 1.5 m. Taking
the density of water 10 kg mº, acceleration due to
gravity 9.8 m s2 and area of base of vessel 100 em.
calculate : (a) the pressure and (b) the thrust, at the
base of vessel. Ans. step by step pls. ​

Answer 1

Explanation:

a) Pressure = height * density * acceleration due to gravity

Pressure = 1.5 * 1000 * 9.8 = 14700 Pa

b) Thrust = Pressure * Area

Thrust = 14700 * 100 = 1470000 N

Answer 2

Correct question :-

A vessel contains water up to a height of 1.5 m. Taking the density of water 10^3kg m^-3, acceleration due to gravity 9.8 m/s^2and area of base of vessel 100 cm 2 , calculate : (a) the pressure and (b) the thrust at the base vessel.

Explanation :-

Given :

Height of water in the vessel,h = 1.5m

Density of the water,ρ = 10^3 kgm^-3

Acceleration due to gravity,g = 9.8 m/s^2

Area of base of vessel,a = 100cm^2

To Find :

Pressure,P

Thrust,at the base of vessel

Solution :

We know,

$\sf{}P=h \rho g$

So,

$\sf{}\implies 1.5\times 10^3 \times9.8$

$\sf{}\therefore 1.47\times 10^4N/m^2$

Therefore,pressure is equal to 1.47 × 10^4N/m^2

We know,

$\sf{}Thrust=Pressure\times area$

So,

$\sf{}\implies1.47\times 10^4\times\dfrac{100}{10000}$       [1cm = 1/100m,so 1cm^2 =1/10000m^2]

$\sf{}\therefore 147N$

Therefore,thrust is equal to 147N