Question

A vessel contains water up to a height of 6 cm. Taking the density of water 1000 kg m-3 and acceleration due to gravity 10 ms-2  calculate the pressure at the base of vessel.​

Answer 1

Answer:

Pressure =ρgh

where ρ=density of water

g=acceleration due to gravity

P=10

3

×9.8×1.5=1.47×10

4

Nm

2

Upthrust = Force exerted = Pressure \times Area

⇒Upthrust=1.47×10

4

Nm

2

×100×10

−4

m=147N

Answer 2

$}Answer :$

Pressure = pgh

Where p = density of water

g = acceleration due to gravity

p = 10

3×9.8×1.5= 1.47 × 10

4

Nm

2

Upthrust = force extend = pressure / time area

= Upthrust = 1.47 × 10

4

Nm

2

×100×10

-4

m= 147

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