a vessel contains water up to height of 1.5 m taking the density of water 10 to the power 3 kg metre cube acceleration due to gravity 9.8 M per second square and area of base level 100cm square calculate the thrust, at the base of the level.. (Answers will be given as brainliest)
Answers
Answered by
35
Hey there!
_______________________
Answer =>
Pressure is given by:
P = hρg
where h is the height or depth of the liquid
ρ is the density of the liquid
g = acceleration due to gravity = 9.8 m/s^2
= 980 cm/s^2
h = 1.5 m
ρ = 1000 kg/m^3
P = 1.5 × 1000 × 9.8
P = 14700 pa
pressue = force/area
thrust = force = pressure × area
= 14700 × 100 × 10^−4
= 147 N
_______________________
Hope this helps you!
_______________________
Answer =>
Pressure is given by:
P = hρg
where h is the height or depth of the liquid
ρ is the density of the liquid
g = acceleration due to gravity = 9.8 m/s^2
= 980 cm/s^2
h = 1.5 m
ρ = 1000 kg/m^3
P = 1.5 × 1000 × 9.8
P = 14700 pa
pressue = force/area
thrust = force = pressure × area
= 14700 × 100 × 10^−4
= 147 N
_______________________
Hope this helps you!
Answered by
8
Answer:
Explanation:P = hdg
P =1.5*9.8*1000
P=14700N/m2
P=Thrust/area
P=14700/100
P=147N
Similar questions