A vessel full of pure acid contains 10L of it, of which 2L are withdrawn. The vessel is then filled with water. Next 2L of the mixture are withdrawn, and again the vessel is filled up with the water. Find the ratio of acid left in vessel with that of original quantity.
Answers
Answered by
2
Answer:
6L
Step-by-step explanation
volume of acid in vessle = 10l
volume of acid after first withdrawn = 10 - 2 =8l
volume of acid after second withdrawn =8 - 2=6l
volume of acid withdrawn after all withdrawns = 8l
volume of acid before withdrawns in vessle = 10l
=10/8
=5/4
=5:4
therefore the ratio of acid left in vessel with that of original quantity is 5:4
Similar questions