a vessel fullof water is in the form of an inverted cone of height 8cm and radiusof its top,which is open is 5cm.100spherical lead balls are dropped into the vessel. onefourth of the water flows out of the vessel.find the radius of spherical ball
Answers
Answered by
146
We know that Volume of cone = πr²h/3
=π*5²*8/3
=200/3π
Now
volume of liquid displaced=volume of balls dropped
1/4(200/3)π=100*4/3πr³
50=100*4r³
50/4=100r³
50/400=r³
1/8=r³
r=1/2=0.5cm
hope helped!
=π*5²*8/3
=200/3π
Now
volume of liquid displaced=volume of balls dropped
1/4(200/3)π=100*4/3πr³
50=100*4r³
50/4=100r³
50/400=r³
1/8=r³
r=1/2=0.5cm
hope helped!
Answered by
32
Hi
We know that volume of sphere is 4/3pie r*r*r
so that
vol. of cone = vol. of sphere
Pi R squared h upon 3 = 4/3 pie r square h
1/4*22/7 * 5*5*8/3 = 4/3*22/7*5*5*5*100
= 0.5cm
We know that volume of sphere is 4/3pie r*r*r
so that
vol. of cone = vol. of sphere
Pi R squared h upon 3 = 4/3 pie r square h
1/4*22/7 * 5*5*8/3 = 4/3*22/7*5*5*5*100
= 0.5cm
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