a vessel has 30 litres of a mixture of milk and water containing 80% milk. how many liters of water must be added to the vessel to reverse the ratio of milk and water?
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A vessel contain 30 ltr of milk in which there is 70 percent of milk and 30 percent is water . Then how much litre of water is needed to make 70 percent of water and 30 percent of milk in the vessel?
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Answer:
90 litres
Step-by-step explanation:
80 % of the total is milk
So balance 20 % of total is water.
Total liters=30
milk=(80/100)*30
=24 liters
Water=(20/100)*30
=6 liters
Ratio of milk to water is
24:6=4:1
A certain liters 'x' is added to milk so that the ratio of milk to water is 1:4
24/(6+x)=1/4
Cross multiply.....
24*4=1*(6+x)
Solve...
96=6+x
6+x=96
x=96-6
x=90 liters
Confirmation...
24:6=4:1 is the ratio of milk to water
90 liters of water is added to the mixture
so water is 6+90=96 liters
So ratio of milk to water is
24:96=1:4 thus it is inverse...
Hope it helps........
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